Помогите решить систему уравнений

x+y=13

√ x+√ y=5

X+y=13

√ x+√ y=5

x+y=13

(√ x+√ y) ^2 = 25

x + y = 13

x + y + 2 √ (xy) = 25

x + y = 13

2 √ (xy) = 25 - 13

x + y = '3

2√ (xy) = 12

x + y = 13

√ (xy) = 6

x + y = 13

xy = 36

y = 13 - x

x * (13 - x) = 36

x^2 - 13x + 36 = 0

D = 169 - 4*1*36 = 169 - 144 = 25

x1 = (13 - 5) / 2

x1 = 8/2

x1 = 4

x2 = (13 + 5) / 2

x2 = 18/2

x2 = 9

y1 = 13 - 4

y2 = 9

y2 = 13 - 9

y2 = 4

Ответ: (4; 9) или (9; 4)