Решите уравнения: х (х+1) (х-2) = 2 (х+1) (х-2); х^3+х^2-х-1=0

(x*x+x) * (x-2) = 2x+2 * (x-2)

x*x*x-2*x+x*x-2x=2x+2x-4

x^3-2x+x^2-2x=2x+2x-4

x^2-2x=2x-4

2x-4=0

x=4/2=2

Х^3+х^2-х-1=0

х^2 (х+1) - (х+1) = 0

(х^2-1) (х+1) = 0

х+1=0

х1=-1

х^2-1=0

х^2=1

х2=-1

х3=1

х (х+1) (х-2) = 2 (х+1) (х-2)

х (х+1) (х-2) - 2 (х+1) (х-2) = 0

(х+1) (х-2) (х-2) = 0

х+1=0

х1=-1

х-2=0

х2=2