Решите уравнение 4x^-2/3 + 3x^-1/3 - 1=0

4X^ (-2/3) + 3X (-1/3) - 1=0;

t=x^-1/3;

4t^2+3t-1=0;

D=3^2-4*4=25;

t1 = (-3-5) / 2*4=-8/8=1;

t2 = (-3+5) / 2*4=2/8=1/4;

t1=-1; t2=1/4;

x^ (-1/3) = - 1; x^ (-1/3) = 1/4;

x1=-1; x2=1/4^-3=4^3=64;