Помогите решить: (10x-3) ^2 = (10x+7) ^2

(10x - 3) ^2 - (10x + 7) ^2 = 0

[ a^2 - b^2 = (a - b) (a + b) ]

(10x - 3 - (10x + 7)) (10x - 3 + 10x + 7) = 0

(10x - 3 - 10x - 7) (10x - 3 + 10x + 7) = 0

- 10 * (20x + 4) = 0 / : (-10)

20x + 4 = 0

20x = - 4

x = - 4/20

x = - 1/5

x = - 0,2