найти нули функции f (x) = 2sin (x+пи/3) + 1

f (x) = 2sin (x+пи/3) + 1

f (x) = 0

2sin (x+пи/3) + 1 = 0

sin (x+пи/3) = - 1/2

x+pi/3 = - pi/6 + 2pik

x = - pi/6-pi/3 + 2pik

x = - pi/2 + 2pik

x+pi/3=7pi/6+2pik

x = 7pi/6 - pi/3 + 2pik

x=5pi/6+2pik