Решите уравнение:

x^3-x^2-3x+2=0

X^3 - x^2 - 3x + 2 = 0;

(x^3 - x^2 - 2 x) - (x - 2) = 0;

x (x^2 - x - 2) - (x-2) = 0;

x (x-2) (x+1) - (x-2) = 0;

(x-2) (x (x+1) - 1) = 0;

(x-2) (x^2 + x - 1) = 0;

x - 2 = 0; ⇒ x = 2;

x^2 + x - 1 = 0;

D = 1+4 = 5;

x = (-1+sgrt5) / 2;

x = (-1 - sgrt5) / 2.