Решите уравнения! (3x^2-2x-5) (x+2) = 0 x^3-4x=0 x^4-6x^2+5=0

(3x^2-2x-5) (x+2) = 0

(x+2) = 0

(3x^2-2x-5) = 0

х1=-2

3x^2-2x-5=0

D = (-2) ^2-4*3 * (-5) = 4+60=64

x2 = - (-2) + 8/2*3=10/6

x3 = - (-2) - 8/2*3=-6/6=-1

x^3-4x=0

x (x^2-4) = 0

x1=0

x^2-4=0

x^2=4

x2=2

x3=-2

x^4-6x^2+5=0

Пусть x^2=t

t^2-6t+5=0

D = (-6) ^2-4*5=16

t1=6+4/2

t1=5

t2=6-4/2

t2=1

x^2=5

x1=корень (5)

x2=-корень (5)

x^2=1

x1=корень (1)

x2=-корень (1)