Решите систему уравнений

xy=6

2x-y=11

Xy = 6

2x - y = 11

xy = 6

y = 2x - 11

x (2x - 11) - 6 = 0

y = 2x - 11

2x² - 11x - 6 = 0

D = 121 + 4•2•6 = 169 = 13²

x1 = (11 + 13) / 4 = 24/4 = 6

x2 = (11 - 13) / 4 = - 1/2

у = 2 х - 11

x = 6

y = 1

x = 6

xy = 6

x = - 1/2

y = - 12

x = - 1/2

Ответ: (6; 1), (-1/2; - 12).