Помогите решить!

tg^x=3 на отрезке [-5 п/2; -п/2]

Tg²x=3

tgx=-√3

x=-π/3+πk

-5π/2≤-π/3+πk≤-π/2

-15≤-2+6k≤-3

-13≤6k≤-1

-13/6≤k≤-1/6

k=-2⇒x=-π/3-2π=-7π/3

k=-1⇒x=-π/3-π=-4π/3

tgx=√3

x=π/3+πk, k∈z

-5π/2≤π/3+πk≤-π/2

-15≤2+6k≤-3

-17≤6k≤-5

-17/6≤k≤-5/6

k=-2⇒x=π/3-2π=-5π/3

k=-1⇒x=π/3-π=-2π/3