Решить уравнение.

1) 2^х-1+2^х-2+2^х-3=448

2) 4^х-3*2=40

1) 2^ (x-1) + 2^ (x-2) + 2^ (x-3) = 448

2^ (x-3) (2^2 + 2^1 + 1) = 448

2^ (x-3) ·7 = 448 | : 7

2^ (x-3) = 64

2^ (x-3) = 2^6

x-3 = 6

x = 9

2) 4^ (x-2) = 20

(x-2) lg4 = lg20

x-2 = lg20/lg4

x = lg20/lg4 + 2