1) log2^2 (1-x) - 2log2 (1-x) = 3

2) 2 log2x=3log3x

3) 2log2x-5logx2=3

Question

Алгебра

Денисья

17 января, 06:53

1) log2^2 (1-x) - 2log2 (1-x) = 3

2) 2 log2x=3log3x

3) 2log2x-5logx2=3

+2

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1)

log₂² (1-x) - 2log₂ (1-x) = 3 1-x>0 x<1

log₂ (1-x) = t ⇒

t²-2t-3=0 D=16

t₁=3 t₂=-1

log₂ (1-x) = 3 1-x=2³ 1-x=8 x₁=-7

log₂ (1-x) = - 1 1-x=2⁻¹ 1-x=0,5 x₂=0,5

1) log2^2 (1-x) - 2log2 (1-x) = 32) 2 log2x=3log3x3) 2log2x-5logx2=3

1) log2^2 (1-x) - 2log2 (1-x) = 3

2) 2 log2x=3log3x

3) 2log2x-5logx2=3