х-5 у=2; х^2-y=10; решить систему

{x - 5y = 2

{x^2 - y = 10

x = 2 - 5y

(2 - 5y) ^2 - y = 10

4 + 25y^2 - 20y - y - 10 = 0

25y^2 - 21y - 6 = 0

D = (-21) 2-4·25· (-6) = 441+600=1041

y1 = (21 + √1041) / 50

y2 = (21 - √1041) / 50

x1 = 2 - (21 + √1041) / 10

x2 = 2 - (21 - √1041) / 10