Решите неравенство

cos (x/2 + 1/4) < = - корень[2] / 2

Решение

cos (x/2 + 1/4) ≤ - √2 / 2

arccos ( - √2/2) + 2πn ≤ x/2 + 1/4 ≤ 2π - arccos (-√2/2) + 2πn, n ∈ Z

3π/4 + 2πn ≤ x/2 + 1/4 ≤ 2π - 3π/4 + 2πn, n ∈ Z

3π/4 + 2πn ≤ x/2 + 1/4 ≤ 5π/4 + 2πn, n ∈ Z

3π/4 - 1/4 + 2πn ≤ x/2 ≤ 5π/4 - 1/4 + 2πn, n ∈ Z

3π/2 - 1/2 + 4πn ≤ x ≤ 5π/2 - 1/2 + 4πn, n ∈ Z