2sinx = - 1 2cos2x = - 2 из кореня 2 sinx=1 sin 2x=1 sin x/2 = 1 2sin x/2=1

1) sinx = 1/2;

x = π/6 + π*n; n∈Z.

2) 2cos2x = - 2;

cos2x = - 1;

1+cos2x = 0;

2cos²x = 0;

cosx=0;

x = π/2 + π*n, n∈Z.

3) √2*sinx = 1;

sinx = 1/√2;

x = (-1) ^ (n) * π/4 + π *, n∈Z

4) sin2x = 1;

2x = π/2+2π*n, n∈Z;

x = π/4 + π*n, n∈Z.

5) sin (x/2) = 1;

x/2 = π/2+2π*n, n∈Z;

x = π+4π*n, n∈Z.

6) 2sin (x/2) = 1;

sin (x/2) = 1/2;

x/2 = π/6 + π*n; n∈Z;

x = π/2 + 2π*n; n∈Z;