Решите уравнение (х-2) (х^2+8 х+16) = 7 (х+4)

(x - 2) (x + 4) ^2 = 7 (x+4)

(x - 2) * (x + 4) ^2 - 7 (x+4) = 0

(x + 4) ((x - 2) (x + 4) - 7) = 0

(x + 4) (x^2 + 2x - 8 - 7) = 0

(x + 4) (x^2 + 2x - 15) = 0

x + 4 = 0

x1 = - 4

x^2 + 2x - 15 = 0

D = 4 + 4*15 = 64

x2 = ( - 2 + 8) / 2 = 6/2 = 3;

x3 = ( - 2 - 8) / 2 = - 10/2 = - 5

Ответ:

- 5; - 4; 3