Помогите решить уравнения по алгебре)

√x-4=5;

√1-3x=2;

√25-x*2=4;

√x*2-256=12;

√x+7=7;

√6x-1=1;

√x+2-81=12;

√625-x*2=15;

X - 4 = 5²

x - 4 = 25

x = 25 + 4

x = 29

1 - 3x = 2²

1 - 3x = 4

- 3x = 4 - 1

- 3x = 3

3x = - 3

x = - 1

25 - x² = 4²

- x² - 16 + 25 = 0

- x² + 9 = 0

x² - 9 = 0

D = b² - 4ac = 0² - 4 * 1 * ( - 9) = 36 = 6²

x₁ = 0 + 6/2 = 3

x₂ = 0 - 6/2 = - 3

x² - 256 = 12²

x² - 256 - 144 = 0

x² - 400 = 0

D = b² - 4ac = 0² - 4 * 1 ( - 400) = 1600 = 40²

x₁ = 0 + 40 / 2 = 20

x₂ = 0 - 40 / 2 = - 20

x + 7 = 7²

x + 7 = 49

x = 49 - 7

x = 42

6x - 1 = 1²

6x = 1 + 1

6x = 2

x = 2/6

x = 1/3

x + 2 - 81 = 12²

x - 79 = 144

x = 144 + 79

x = 223

625 - x² = 15²

- x² + 625 = 225

- x² = 225 - 625

- x² = - 400

x² = 400

x - 400 = 0

D = b² - 4ac = 0² - 4 * 1 * ( - 400) = 1600 = 40²

x₁ = 0 + 40 / 2 = 20

x₂ = 0 - 40 / 2 = - 20