Решить уравнения

3 tg (x - π/6) = √3

2 sin (4x - π) = √2

1) 3tg (x-π/6) = √3

tg (x-π/6) = √3/3

x-π/6=π/6+k.π

x=π/6+π/6+k.π

x=π/3+k.π, k∈Z

2) 2. sin (4x-π) = √2

sin (4x-π) = √2/2

a) 4x-π=π/4+2k.π

4x=π+π/4 + 2k.π=5/4.π+2k.π

x=5π/16+k.π/2

b) 4x-π=3π/4+2k.π

4x=π+3π/4 + 2k.π=7π/4+2k.π

x=7π/16+k.π/2

k∈Z