Как решить (2/2+m - m/m-2 - 4m/4-m^²) : (2/2+m + m/2-m + 4m/m^²-4)

Question

Алгебра

Борюша

30 июля, 08:50

Как решить (2/2+m - m/m-2 - 4m/4-m^²) : (2/2+m + m/2-m + 4m/m^²-4)

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Андроник · Answer 1

2/2+m - m/m-2 - 4m/4-m^² = 2/2+m + m/2-m - 4m/4-m^²=

(2 (2-m) + m (m+2) - 4m) / (4-m^2) = (4-2m+m^2+2m-4m) / (4-m^2) =

(m^2-4m+4) / (m^2-4) = (m-2) (m-2) / (2-m) (m+2) =

- (m-2) / (m+2).

(2/2+m + m/2-m + 4m/m^²-4) = (2 (2-m) - m (2+m) + 4m) / (m^²-4) = (4-2m-2m-m^2+4m) / (m-2) (m+2) = (4-m^2) / (m^2-4) = - 1

- (m-2) / (m+2) : (-1) = (m-2) / (m+2)