Решите систему уравнений

y-x=2

y^2-2xy-x^2=-28

Решение

y - x = 2

y^2 - 2xy - x ^2 = - 28

y = x + 2

(x+2) ^2 - 2*x (x+2) - x^2 = - 28

x^2 + 4x + 4 - 2x^2 - 4x - x^2 = - 28

- 2x^2 = - 32

x^2 = 16

x1 = - 4

x2 = 4

y1 = - 4 + 2

y1 = - 2

y2 = 2 + 2

y2 = 4

Ответ: ( - 4; - 2) (4; 4)