решите неравенство - 2x^2-5x-2<0

-2x^2-5x-2<0

2x^2 + 5x + 2 > 0

2x^2 + 5x + 2 = 0

Δ = 25 - 16 = 9

x1 = ( - 5+3) / 4 = - 2/4 = - 1/2

x2 = ( - 5-3) / 4 = - 8/4 = - 2

2 (x + 1/2) (x + 2) = 0

(2x + 1) (x+2) > 0

x ∈ ( - беск; - 2) ∨ ( - 1/2; + бес)