1-cos2x=sinx Помогите

1-cos2x=sinx

1 - (cos ²x-sin ²x) - sinx=0

cos²x+sin²x-cos²x+sin²x-sinx=0

2sin²x-sinx=0

sinx * (2sinx-1) = 0

1) sinx=0

x=πn, n∈Z

2) 2sinx-1=0

2sinx=1

sinx=1/2

x (1) = π/6 + 2πn, n∈Z

x (x) = 5π/6 + 2πn, n∈Z

Ответ: πn, n∈Z; π/6 + 2πn, n∈Z; 5π/6 + 2πn, n∈Z