Log3 (3x-1) + log3 (1+x) = 1+log3 (x+3)

Log3 ((3x-1) * (1+x)) = log3 3 + log3 (x+3)

log3 ((3x-1) * (1+x) = log3 (3 * (x+3))

(3x-1) * (1+x) = 3 * (x+3)

3x+3x²-1-x=3x+9

3x²-x-10==0

D = 1+120 = 121

x1 = (1+11/6) = 2

x2 = (1-11/6) = 10/6 = 5/3 = 1 целая (2/3)

ответ: 1 целая 2/3

2