Решите уравнение: 2sin 2x + ^3=0.

cos (-x/3) = ^2/2.

tg (4x-1) = ^3/3.

sin (4-3x/2) = - 1.

ctg (-7x) = - 1

cos (-x/3) = ^2/2.

-x/3=+-π/4+2πn

x=+-3π/4+6πn

tg (4x-1) = ^3/3.

4x-1=π/6+πn

4x=1+π/6+πn

x=1/4+π/24+πn/4

sin (4-3x/2) = - 1.

4-3x/2=-π/2+2πn

-3x/2=-4-π/2+2πn

x=8/3+π/3+2πn/3

ctg (-7x) = - 1

-7x=3π/4+πn

x=-3π/28+πn/7