Sqrt3sin2x+cos2x<или равно 1

√3 * sin (2x) + cos (2x) <=1

√3 * 2sin (x) cos (x) + cos² (x) - sin² (x) < = cos² (x) + sin² (x)

2√3 * sin (x) cos (x) < = 2sin² (x)

√3 * cos (x) < = sin (x)

√3 * ctg (x) <=1

ctg (x) < = 1/√3

x<=π/6 + πn, n=1,2,3 ...