Решите уравнение:

3*3^2x - 7*12^x + 4*4^2x = 0

3 * (3^2x) - 7*912^x) + 4*04^2x) = 0

3 * (3^2x) - 7 * (3^x) * (4^x) + 4 * (4^2x) = 0 / (4^2x)

3*[ (3/4) ^2x] - 7*[ (3/4) ^x] + 4 = 0

(3/4) ^x = z

3 * (z^2) - 7z + 4 = 0

D = 49 - 4*3*4 = 1

z1 = (7 - 1) / 6

z1 = 1

z2 = (7 + 1) / 6

z2 = 4/3

1) (3/4) ^x = 1

(3/4) ^x = (3/4) ^0

x1 = 0

2) (3/4) ^x = 4/3

(3/4) ^x = (3/4) ^ (-1)

x2 = - 1