Решите уравнение 2sin^2x-sinx=1

2sin²x - sinx = 1

заменим sinx = a

2a² - a - 1 = 0

D = 1+4*2=9

a = (1 + 3) / 4 = 1 a = (1 - 3) / 4 = - 1/2

sinx = a = 1 sinx = - 1/2

x = arcsin1 = pi/2 + pi*n x = - pi/3 + 2pi*n x = - 2pi/3 + 2pi*n