Векторная алгебра:

найти вектор m при a (1; 5; 2) b (1; -3; -2) с (0; 3; 1) m 2a+4b-3c

A (1; 5; 2)

b (1; -3; -2)

c (0; 3; 1)

m = 2a+4b-3c

2a = (2; 10; 4)

4b = (4; -12; -8)

3c = (0; 9; 3)

m = (2; 10; 4) + (4; -12; -8) - (0; 9; 3) = (2+4-0); (10-12-9); (4-8-3) = (6; -11; -7)

m = (6; -11; -7)