Решение уравнений, в которых произведение двучленов равно нулюРешите уравнения: (3x - 1) (x + 5) = 0; (2x + 3) (x + 1) = 0; (1 + 2x) (3x - 2) = 0; (5x - 3) (2 + 3x) = 0.

(3 х-1) (х+5) = 0

3 х+15 х-х-5=0

16 х=5

х=16:5

х=3,2

(2 х+3) (х+1) = 0

2 х+2 х+3 х+3=0

7 х=-3

х=7: (-3)

х=-7/3

(1+2 х) (3 х-2) = 0

3 х-2+6 х-4 х=0

5 х=2

х=5:2

х=2.5

(5 х-3) (2+3 х) = 0

10 х+15 х-6-9 х=0

16 х=6

х=16:6

х=16/6

(3x - 1) (x + 5) = 0

3x - 1 = 0 = > x = 1/3

or

x + 5 = 0 = >x = - 5

(2x + 3) (x + 1) = 0

2x + 3 = 0 = > x = - 1,5

or

x + 1 = 0 = > x = - 1

(1 + 2x) (3x - 2) = 0

1 + 2x = 0 = > x = - 0,5

or

3x - 2 = 0 = > x = 2/3

(5x - 3) (2 + 3x) = 0

5x - 3 = 0 = > x = 0,6

or

2 + 3x = 0 = > x = - 2/3