Решите уравнения

3x^2=2x+4

(x-1) (2x+3) = - 2

x^2+7/2=4x

1

3x²-2x-4=0

D=4+48=52

x1 = (2-2√13) / 6 = (1-√13) / 3

x2 = (1+√13) / 3

2

2x²+3x-2x-3+2=0

2x²+x-1=0

D=1+8=9

x1 = (-1-3) / 4=-1

x2 = (-1+3) / 4=1/2

3

x²+7=8x

x²-8x+7=0

x1+x2=8 U x1*x2=7

x1=1 U x2=7