Решите систему уравнений

0,3 х-0,4 у=0,1,

{

3 х+4 у=-13.

{0.3x-0.4y = 0.1 0.3x = 0.1 + 0.4y x = 1/3 + 4/3y x = 1/3 + 4/3 * (-2) = 1/3 - 8/3 = - 7/3

{3x+4y = - 13 3 * (1/3 + 4/3y) + 4y = - 13 3 + 4y + 4y = - 13 8y = - 16 y = - 16/8 = - 2

Ответ. (-2 1/3; - 2)

3x-4y=1

3x+4y=-13

6x=-12

x=-2

-6+4y=-13

4y=-7

y=-7/4

(-2; -7/4)