1) sinx · cosx · cos2x = √3/8

2) cos²x - sin²x - sinx = 0

sinx * cosx * cos2x = √3/8

1/2sin2x*cos2x = √3/8

1/2sin4x = √3/4

sin4x = √3/2

4x = (-1) ^n * π/3+πn, n∈z

x = (-1) ^n * π/12+π/4*n, n∈z

Ответ. x = (-1) ^n * π/12+π/4n, n∈z

cos²x - sin²x - sinx = 0

cos2x-sinx=0

1-2sin²x-sinx=0

2sin²x+sinx-1=0

sinx=-1 или sinx=1/2

x=-π/2+2πn, n∈z или x = (-1) ^n * π/6+πk, k∈z

Ответ. x=-π/2+2πn, n∈z

x = (-1) ^n * π/6+πk, k∈z