2x (x-3) ^2-x^2 (x-3) = 0

x1=

x2=

x3=

Решите уравнение

2x (x-3) ²-x² (x-3) = 0

2x (x²-6x+9) - x³+3x²=0

2x³-12x²+18x-x³+3x²=0

x³-9x²+18x=0

x (x²-9x+18) = 0

x=0

x²-9x+18=0

D = (-9) ²-4*1*18=81-72=9

x1 = (9+3) / 2=6

x2 = (9-3) / 2=3

Ответ: x1=0, x2=3, x3=6

2x (x-3) ²-x² (x-3) = 0

x=0

x=3

x=6