Решите систему уравнений:

{xy=12

{2x+2y-xy=2

{х=12/у

{2x+2y-xy=2 2 * (12/у) + 2 у - (12/у) * у - 2 = 0

(24 + 2 у^2) / y - 14 = 0

2y^2 - 14y + 24 = 0

x1=12/4 = 3 D = (-14) ² - 4 * 2 * 24 = 196 - 192 = 4

x2 = 12/3 = 4 y1 = ( - (-14) + 2) / 2*2 = 4

y2 = ( - (-14) - 2) / 2*2 = 3