Решить уравнение

Sin2 x=cos x

Решение

sin2x = cosx

2sinx*cosx - cosx = 0

cosx * (2sinx - 1) = 0

1) cosx = 0

x = π/2 + πk, k ∈ Z

2) 2sinx - 1 = 0

sinx = 1/2

x = (-1) ^n * arcsin (1/2) + πn, n ∈ Z

x = (-1) ^n * (π/6) + πn, n ∈ Z