Sin^2 (x-pi/4) = 1/2?

Извлекаем корень из обоих частей равенства: sin (x1-π/4) = 1/√2 и

sin (x2-π/4) = - 1/√2

Для sin (x1-π/4) = 1 / √2⇒x11-π/4=π/4⇒x11=π/2+2*π*N и

x12-π/4=3*π/4⇒x12=π + 2*π*N

Для sin (x1-π/4) = - 1 / √2⇒x21-π/4=5*π/4⇒x21=1,5*π+2*π*N и

x22-π/4=7*π/4⇒x22=2*π.

Ответ: x11=π/2+2*π*N; x12=π + 2*π*N; x21=1,5*π+2*π*N; x22=2 * π.