Cos6x+sin6x корень из 2 cos (3 пи-3 х) = 1

Cos6x+√2cos (3 п/2-3 х) = 1

Cos6x-√2sin3x=1

1-2sin^2 (3x) - √2sin3x=1

-2sin^2 (3x) - √2sin3x=0

sin3x (-2sin3x-√2) = 0

sin3x=0

3x=пn, n€z

x=пn/3, n€z

-2sin3x-√2=0

sin3x=-√2/2

3x = (-1) ^n+1 п/4+пn, n€z

x=1/3 * (-1) ^n+1 п/4+пn/3, n€z