Sin2x-2sinx+2sin^2 x/2=0

2sinxcosx-2sinx+2 * ((1-cosx) / 2) = 0

2sinxcosx-2sinx+1-cosx=0

2sinx (cosx-1) + 1-cosx=0

2sinx (cosx-1) - (cosx-1) = 0

(cosx-1) (2sinx-1) = 0

cosx=1 = > x=2pi*n, n=0,1,2,3 ...

sinx=1/2 = > x = (-1) ^k * pi/6 + pi*k, k=0,1,2,3 ...