2cosx sinx = - 1/2 ребятки - помогите

Sin2x = - 1/2

2x = arcsin ( - 1/2)

2x = - π/6

х = - π/12

Решение

2cosx sinx = - 1/2

sin2x = - 1/2

2x = (-1) ^n * arcsin (-1/2) + πn, n ∈ Z

2x = (-1) ^ (n+1) * arcsin (1/2) + πn, n ∈ Z

2x = (-1) ^ (n+1) * (π/6) + πn, n ∈ Z

x = (-1) ^ (n+1) * (π/12) + πn/2, n ∈ Z