По теореме виет 67 х2-105 х+38=0

67x²-105x+38=0

x1+x2 = 105/67

x1*x2 = 38/67

x1=105/67-x2

(105/67-x2) * x2=38/67

((105-67x2) / 67) * x2=38/67 I*67

105x2-67x2²=38

67x2²-105x2+38=0

D = 11025 - 10184 = 841

(x2) 1 = (105-29) / 134 = 76/134 = 38/67

(x2) 2 = (105+29) / 134 = 1

Проверяем:

(x1) 1 = 105/67-38/67 = 1

(x1) 2 = 105/67-1 = 38/67

Корни: 1 и 38/67