Решыте ситему уравнений

(y+x=3

x2+y2=49) - ето ситема

x=3-y

(3-y) ^2+y^2=49

9-6y+y^2+y^2-49=0

2y^2-6y-40=0 : 2

y^2-3y-20=0

D=9+80=89

y1 = (3+√89) / 2

y2 = (3-√89) / 2

x1=3 - (3+√89) / 2 = (6-3-√89) / 2 = (3-√89) / 2

x2=3 - (3-√89) / 2 = (6-3+√89) / 2 = (3+√89) / 2