Решить систему: 2 (х+у) = 8

14-3 (х-у) = 5 у-х

14-3 (x-y) = 5y-x

2 (x+y) = 8

14-3x+3y=5y-x

2x+2y=8

14-3x+3y-5x+x=0

2x+2y=8

14-8x+3y+x=0

x+y=4

x=4-y

14-8 (4-x) + 3 (4+x) + (4+x) = 0

14-32+8x+12+3x+4+x=0

12x-2=0

12x=2

x=6

x=6

6=4-y

y=4-6

y=-2

x=6y=-2