Помогите решить неравенства: 2cos (pi-x) <=1 и - 4tg (x+pi/8) <=1

1) 2cos (π - x) ≤ 1

cos (π - x) ≤ 1/2

cos (x - π) ≤ 1/2

arccos (1/2) + 2πn ≤ x - π ≤ 2π - arccos (1/2) + 2πn, n∈Z

π/3 + 2πn ≤ x - π ≤ 2π - π/3 + 2πn, n∈Z

π/3 + 2πn ≤ x - π ≤ 5π/3 + 2πn, n∈Z

π/3 + π + 2πn ≤ x ≤ 5π/3 + π + 2πn, n∈Z

4π/3 + 2πn ≤ x ≤ 8π/3 + 2πn, n∈Z

2) - 4tg (x + π/8) ≤ 1

tg (x + π/8) ≥ - 1/4

arctg (-1/4) + πn ≤ x ≤ π/2 + πn, n∈Z

- arctg (1/4) - π/8 + πn ≤ x ≤ π/2 - π/8 + πn, n∈Z

- arctg (1/4) - π/8 + πn ≤ x ≤ 3π/8 + πn, n∈Z