Решите уравнение: 2x^4+5x^3-5x-2=0

2x^4 + 5x³ - 5x - 2 = 0

2 (x⁴-1) + 5x (x²-1) = 0

2 (x²-1) (x²+1) + 5x (x²-1) = 0

(2 (x²+1) + 5x) (x²-1) = 0

(2x² + 5x + 2) (x²-1) = 0

x² - 1 = 0 x = 1; x = - 1

2x²+5x + 2 = 0

x1 = - 2; x2 = 0,5