Решить тригонометрическое уравнение

sin3x+sinx-2sin2x=2cos^2x-2cosx

2sin2xcosx-2sin2x=2cos²x-2cosx

2sin2x (cosx-1) - 2cosx (cosx-1) = 0

(cosx-1) (4sinxcosx-2cosx) = 0

(cosx-1) * 2cosx (2sinx-1) = 0

cosx=1⇒x=2πn

cosx=0⇒x=π/2+πn

sinx=1/2⇒x = (-1) ^n*π/6+πn