6 в степени х2-2 х=1

loga (4b2-1) - loga (2b-1), еслм а=2, b = - 3/8

1) 6 ^ х ² - 2 х=1

6^ (x^2-2x) = 6^0

x^2-2x=0

x * (x-2) = 0

x=0

или

х-2-0

х=2

2) loga (4b^2-1/2b-1) = loga ((b-1/2) * (b+1/2) / b-1/2) = loga (b+1/2)

loga (b-+1/2) = log2_ (-3/8+1/2) = log2_ (-3+4/8) = log2_ (1/8) = log2_ (2^ (-3)) = - 3