Реакция ионного обмена

ZnCl2+NaOH

H3PO4+KOH

1) ZnCl2 + 2NaOH = Zn (OH) 2 / + 2 NaCl

2 + - + - + -

Zn + 2Cl + 2Na + 2OH = Zn (OH) 2 / + 2Na + 2Cl

2 + -

Zn+2OH=Zn (OH) 2

2) H3PO4 + 3KOH = K3PO4+3H2O

+ 2 - + - + 2-

3H + PO4 + 3K+3OH=3K + PO4 + 3H2O

+ -

3H+3OH=3H2O