A - (3; -4), b - (2; 6), c - (-2; 0), найти P-?

Решение

A - (3; -4), b - (2; 6), c - (-2; 0)

AB = √[ (2-3) ² + (6 + 4) ²] = √ (1 + 100) = √101

AC = √[ (-2 - 3) ² + (0 + 4) ²] = √[ (-5) ² + 4²] = √ (25 + 16) = √41

BC = √[ ( - 2 - 2) ² + (0-6) ²] = √[ (-4) ² + (-6) ²] = √ (16 + 36) = √42

P = AB + AC + BC = √101 + √41 + √42