2cos^2x * (-П/2-x) + sqrt (3) * sin2x=0

2cos²x ( - (π/2+x) + √3sin2x=0

2sin²x+2√3sinxcosx=0

2sinx (sinx+√3cosx) = 0

1) 2sinx=0

sinx=0

x=πn

2) sinx+√3cosx=0 |·1/2

1/2·sinx+√3/2·cosx=0

cosπ/3·six+sinπ/3·cosx=0

sin (π/3+x) = 0

π/3+x=πn, n∈Z

x=πn-π/3, n∈Z