Решите уравнение 5x²-12x+4=0

5x^2 - 12x + 4 = 0, в = 12, а = 5, c = 4

D = в^2 - 4*a*c;

D = 12^2 - 4*5*4 = 144 - 80 = 64; √64 = 8;

x1 = (-В + √D) / 2a

x1 = ( - (-12) + 8) / 2*5 = 20/10 = 2

x2 = ( - B - √D) / 2*a

x2 = ( - (-12) - 8) / 10 = 4/10 = 0.4

Ответ:x1 = 2; x2 = 0.4