Решите √2 х-1+√х-2=√х+1

2x-1≥0 x≥1/2

x-2≥0 x≥2 ⇒x≥2⇒x∈I2; ∞)

x+1≥0 x≥-1

2x-1=x - 2-2√ (x+1) (x-2) + x+1

-2√x²-x-2=0

√x²-x-2=0

x²-x-2=0

D=1+4*2=9

X₁ = (1+3) : 2=2, X₂ = (1-3) : 2=-1,

-1 ne ≥ 2, ne reshenie

2≥2 ono reshenie⇒x=2